A disc of mass M and radius | vedclass

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Question

Angular momentum of disc about origin is $:$

$\mathrm{L}=\mathrm{I} \omega+\mathrm{mV}\left(\mathrm{r}_{1}\right)$

$=\frac{\mathrm{MR}^{2}}{2} \

Vedclass · Accepted Answer

$\frac {3}{2} MR^2\omega $

Vedclass · Answer

Angular momentum of disc about origin is $:$

$\mathrm{L}=\mathrm{I} \omega+\mathrm{mV}\left(\mathrm{r}_{1}\right)$

$=\frac{\mathrm{MR}^{2}}{2} \omega+\mathrm{mV}(\mathrm{R})$

$=\frac{\mathrm{MR}^{2}}{2} \omega+\mathrm{M}(\omega \mathrm{R})(\mathrm{R})$

$=\frac{3}{2} \mathrm{M} \omega \mathrm{R}^{2}$

A disc of mass $M$ and radius $R$ is rolling with angular speed $\omega $ on a horizontal plane as shown. The magnitude of angular momentum of the disc about the origin $O$ is

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